(x+4)(-x+2)=-x^2-4x

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Solution for (x+4)(-x+2)=-x^2-4x equation:



(x+4)(-x+2)=-x^2-4x
We move all terms to the left:
(x+4)(-x+2)-(-x^2-4x)=0
We add all the numbers together, and all the variables
-(-x^2-4x)+(x+4)(-1x+2)=0
We get rid of parentheses
x^2+4x+(x+4)(-1x+2)=0
We multiply parentheses ..
x^2+(-1x^2+2x-4x+8)+4x=0
We get rid of parentheses
x^2-1x^2+2x-4x+4x+8=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4

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